update column with random string
DECLARE @v TABLE (x VARCHAR(50)) INSERT INTO @v VALUES — list of strings that column will be updated with (’37845840’),(’34879335’),(’33879336’),(’37855840’); DECLARE cursor1 CURSOR FOR SELECT <TABLE_ID> FROM <SOME_TABLE>; DECLARE @id INT; OPEN cursor1 FETCH NEXT FROM cursor1 INTO @id WHILE @@FETCH_STATUS=0 BEGIN UPDATE <SOME_TABLE> SET <UPDATED_COLUMN> = ( SELECT x FROM ( Read more about update column with random string[…]